(0) Obligation:

Clauses:

select(X, .(X, Xs), Xs).
select(X, .(Y, Xs), .(Y, Zs)) :- select(X, Xs, Zs).

Query: select(a,g,a)

(1) PrologToDTProblemTransformerProof (SOUND transformation)

Built DT problem from termination graph DT10.

(2) Obligation:

Triples:

selectA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) :- selectA(X1, X4, X5).
selectA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) :- selectA(X1, X4, X5).

Clauses:

selectcA(X1, .(X1, X2), X2).
selectcA(X1, .(X2, .(X1, X3)), .(X2, X3)).
selectcA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) :- selectcA(X1, X4, X5).
selectcA(X1, .(X2, .(X1, X3)), .(X2, X3)).
selectcA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) :- selectcA(X1, X4, X5).

Afs:

selectA(x1, x2, x3)  =  selectA(x2)

(3) TriplesToPiDPProof (SOUND transformation)

We use the technique of [DT09]. With regard to the inferred argument filtering the predicates were used in the following modes:
selectA_in: (f,b,f)
Transforming TRIPLES into the following Term Rewriting System:
Pi DP problem:
The TRS P consists of the following rules:

SELECTA_IN_AGA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) → U1_AGA(X1, X2, X3, X4, X5, selectA_in_aga(X1, X4, X5))
SELECTA_IN_AGA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) → SELECTA_IN_AGA(X1, X4, X5)

R is empty.
The argument filtering Pi contains the following mapping:
selectA_in_aga(x1, x2, x3)  =  selectA_in_aga(x2)
.(x1, x2)  =  .(x1, x2)
SELECTA_IN_AGA(x1, x2, x3)  =  SELECTA_IN_AGA(x2)
U1_AGA(x1, x2, x3, x4, x5, x6)  =  U1_AGA(x2, x3, x4, x6)

We have to consider all (P,R,Pi)-chains

Infinitary Constructor Rewriting Termination of PiDP implies Termination of TRIPLES

(4) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

SELECTA_IN_AGA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) → U1_AGA(X1, X2, X3, X4, X5, selectA_in_aga(X1, X4, X5))
SELECTA_IN_AGA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) → SELECTA_IN_AGA(X1, X4, X5)

R is empty.
The argument filtering Pi contains the following mapping:
selectA_in_aga(x1, x2, x3)  =  selectA_in_aga(x2)
.(x1, x2)  =  .(x1, x2)
SELECTA_IN_AGA(x1, x2, x3)  =  SELECTA_IN_AGA(x2)
U1_AGA(x1, x2, x3, x4, x5, x6)  =  U1_AGA(x2, x3, x4, x6)

We have to consider all (P,R,Pi)-chains

(5) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 1 less node.

(6) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

SELECTA_IN_AGA(X1, .(X2, .(X3, X4)), .(X2, .(X3, X5))) → SELECTA_IN_AGA(X1, X4, X5)

R is empty.
The argument filtering Pi contains the following mapping:
.(x1, x2)  =  .(x1, x2)
SELECTA_IN_AGA(x1, x2, x3)  =  SELECTA_IN_AGA(x2)

We have to consider all (P,R,Pi)-chains

(7) PiDPToQDPProof (SOUND transformation)

Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

SELECTA_IN_AGA(.(X2, .(X3, X4))) → SELECTA_IN_AGA(X4)

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.

(9) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • SELECTA_IN_AGA(.(X2, .(X3, X4))) → SELECTA_IN_AGA(X4)
    The graph contains the following edges 1 > 1

(10) YES